Optimal. Leaf size=815 \[ \frac{3 C \tan (c+d x) (\sec (c+d x) a+a)^{4/3}}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (\sec (c+d x)+1),\sec (c+d x)+1\right ) (\sec (c+d x)+1) \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{11 d \sqrt{1-\sec (c+d x)}}+\frac{15 \sqrt [3]{2} \sqrt [4]{3} a C E\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt{\frac{(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d (1-\sec (c+d x)) (\sec (c+d x)+1)^{2/3} \sqrt{-\frac{\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}}}+\frac{5\ 3^{3/4} \left (1-\sqrt{3}\right ) a C \text{EllipticF}\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right ),\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt{\frac{(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7\ 2^{2/3} d (1-\sec (c+d x)) (\sec (c+d x)+1)^{2/3} \sqrt{-\frac{\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}}}+\frac{3 a C \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d}-\frac{15 \left (1+\sqrt{3}\right ) a C \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d (\sec (c+d x)+1)^{2/3} \left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )} \]
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Rubi [A] time = 1.01616, antiderivative size = 815, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 12, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {4055, 3924, 3779, 3778, 136, 3828, 3827, 50, 63, 308, 225, 1881} \[ \frac{3 C \tan (c+d x) (\sec (c+d x) a+a)^{4/3}}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (\sec (c+d x)+1),\sec (c+d x)+1\right ) (\sec (c+d x)+1) \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{11 d \sqrt{1-\sec (c+d x)}}+\frac{15 \sqrt [3]{2} \sqrt [4]{3} a C E\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt{\frac{(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d (1-\sec (c+d x)) (\sec (c+d x)+1)^{2/3} \sqrt{-\frac{\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}}}+\frac{5\ 3^{3/4} \left (1-\sqrt{3}\right ) a C F\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt{\frac{(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7\ 2^{2/3} d (1-\sec (c+d x)) (\sec (c+d x)+1)^{2/3} \sqrt{-\frac{\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}}}+\frac{3 a C \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d}-\frac{15 \left (1+\sqrt{3}\right ) a C \tan (c+d x) \sqrt [3]{\sec (c+d x) a+a}}{7 d (\sec (c+d x)+1)^{2/3} \left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )} \]
Antiderivative was successfully verified.
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Rule 4055
Rule 3924
Rule 3779
Rule 3778
Rule 136
Rule 3828
Rule 3827
Rule 50
Rule 63
Rule 308
Rule 225
Rule 1881
Rubi steps
\begin{align*} \int (a+a \sec (c+d x))^{4/3} \left (A+C \sec ^2(c+d x)\right ) \, dx &=\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}+\frac{3 \int (a+a \sec (c+d x))^{4/3} \left (\frac{7 a A}{3}+\frac{4}{3} a C \sec (c+d x)\right ) \, dx}{7 a}\\ &=\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}+A \int (a+a \sec (c+d x))^{4/3} \, dx+\frac{1}{7} (4 C) \int \sec (c+d x) (a+a \sec (c+d x))^{4/3} \, dx\\ &=\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}+\frac{\left (a A \sqrt [3]{a+a \sec (c+d x)}\right ) \int (1+\sec (c+d x))^{4/3} \, dx}{\sqrt [3]{1+\sec (c+d x)}}+\frac{\left (4 a C \sqrt [3]{a+a \sec (c+d x)}\right ) \int \sec (c+d x) (1+\sec (c+d x))^{4/3} \, dx}{7 \sqrt [3]{1+\sec (c+d x)}}\\ &=\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}-\frac{\left (a A \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{(1+x)^{5/6}}{\sqrt{1-x} x} \, dx,x,\sec (c+d x)\right )}{d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}-\frac{\left (4 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{(1+x)^{5/6}}{\sqrt{1-x}} \, dx,x,\sec (c+d x)\right )}{7 d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}\\ &=\frac{3 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) (1+\sec (c+d x)) \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{11 d \sqrt{1-\sec (c+d x)}}+\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}-\frac{\left (5 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} \sqrt [6]{1+x}} \, dx,x,\sec (c+d x)\right )}{7 d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}\\ &=\frac{3 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) (1+\sec (c+d x)) \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{11 d \sqrt{1-\sec (c+d x)}}+\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}-\frac{\left (30 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{x^4}{\sqrt{2-x^6}} \, dx,x,\sqrt [6]{1+\sec (c+d x)}\right )}{7 d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}\\ &=\frac{3 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) (1+\sec (c+d x)) \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{11 d \sqrt{1-\sec (c+d x)}}+\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}+\frac{\left (15 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{2^{2/3} \left (-1+\sqrt{3}\right )-2 x^4}{\sqrt{2-x^6}} \, dx,x,\sqrt [6]{1+\sec (c+d x)}\right )}{7 d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}+\frac{\left (15\ 2^{2/3} \left (1-\sqrt{3}\right ) a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{2-x^6}} \, dx,x,\sqrt [6]{1+\sec (c+d x)}\right )}{7 d \sqrt{1-\sec (c+d x)} (1+\sec (c+d x))^{5/6}}\\ &=\frac{3 a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{7 d}+\frac{3 \sqrt{2} a A F_1\left (\frac{11}{6};\frac{1}{2},1;\frac{17}{6};\frac{1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) (1+\sec (c+d x)) \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{11 d \sqrt{1-\sec (c+d x)}}+\frac{3 C (a+a \sec (c+d x))^{4/3} \tan (c+d x)}{7 d}-\frac{15 \left (1+\sqrt{3}\right ) a C \sqrt [3]{a+a \sec (c+d x)} \tan (c+d x)}{7 d (1+\sec (c+d x))^{2/3} \left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )}+\frac{15 \sqrt [3]{2} \sqrt [4]{3} a C E\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \sqrt [3]{a+a \sec (c+d x)} \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right ) \sqrt{\frac{2^{2/3}+\sqrt [3]{2} \sqrt [3]{1+\sec (c+d x)}+(1+\sec (c+d x))^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}} \tan (c+d x)}{7 d (1-\sec (c+d x)) (1+\sec (c+d x))^{2/3} \sqrt{-\frac{\sqrt [3]{1+\sec (c+d x)} \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}}}+\frac{5\ 3^{3/4} \left (1-\sqrt{3}\right ) a C F\left (\cos ^{-1}\left (\frac{\sqrt [3]{2}-\left (1-\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}}{\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right ) \sqrt [3]{a+a \sec (c+d x)} \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right ) \sqrt{\frac{2^{2/3}+\sqrt [3]{2} \sqrt [3]{1+\sec (c+d x)}+(1+\sec (c+d x))^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}} \tan (c+d x)}{7\ 2^{2/3} d (1-\sec (c+d x)) (1+\sec (c+d x))^{2/3} \sqrt{-\frac{\sqrt [3]{1+\sec (c+d x)} \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt{3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}}}\\ \end{align*}
Mathematica [F] time = 27.5295, size = 0, normalized size = 0. \[ \int (a+a \sec (c+d x))^{4/3} \left (A+C \sec ^2(c+d x)\right ) \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.173, size = 0, normalized size = 0. \begin{align*} \int \left ( a+a\sec \left ( dx+c \right ) \right ) ^{{\frac{4}{3}}} \left ( A+C \left ( \sec \left ( dx+c \right ) \right ) ^{2} \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \sec \left (d x + c\right )^{2} + A\right )}{\left (a \sec \left (d x + c\right ) + a\right )}^{\frac{4}{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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